How to retrieve a default row when a mysqli_stmt_fetch fails?

Problem :

I've got a simple PHP script that pull a row from a MySQL database based on a URL GET parameter, just an int called, say, ID.

If the GET parameter were to be an invalid ID for the database, such as someone enters an int that's not a row in the DB, or they try and enter a character or something, I'd like to display a default record.

The following code actually works, but I feel that it's bad code. I'm just not sure why, or what I should do. I know I should validate ID is an int before I run the database queries, but that doesn't solve what to do when an integer that is an invalid ID is used.

So to make this a proper question, how should I recover from mysqli_stmt_fetch returning false?

Go easy, I know I'm a nub :-)

$ID = (int)$_GET["id"];

$query = "SELECT `col1`, `col2`, `col3` FROM `table` WHERE `ID` = ?";

if ($stmt = mysqli_prepare($connection, $query))
    mysqli_stmt_bind_param($stmt, "i", $ID);
    mysqli_stmt_bind_result($stmt, $var1, $var2, $var3);
    if (!mysqli_stmt_fetch($stmt))
        $ID = 1; //A record I know exists and will always exist
        mysqli_stmt_bind_param($stmt, "i", $ID);
        mysqli_stmt_bind_result($stmt, $var1, $var2, $var3);

OK, so with some feedback and experimentation I've cast the ID as an int in PHP and changed the SQL query to this:

SELECT `col1`, `col2`, `col3`
FROM `table`
WHERE `ID` = ?
SELECT `col1`, `col2`, `col3`
FROM `table`
WHERE `ID` = 1

This works for all cases I can think of and seems to be secure. Any problems? Any better than what I had?

Solution :

First check incoming $ID for char and so and set it to value that never be as ID in your table, then use query

SELECT col1, col2, col3 FROM table WHERE ID = :id
union all 
SELECT col1, col2, col3 FROM table WHERE ID = 1 /* may :defaut_id if */
where not exist (select 1 from table WHERE ID = :id)

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